x^2+5.6x-1.12=0

Solution for x^2+5.6x-1.12=0 equation:

x^2+5.6x-1.12=0

a = 1; b = 5.6; c = -1.12;
Δ = b2-4ac
Δ = 5.62-4·1·(-1.12)
Δ = 35.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.6)-\sqrt{35.84}}{2*1}=\frac{-5.6-\sqrt{35.84}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.6)+\sqrt{35.84}}{2*1}=\frac{-5.6+\sqrt{35.84}}{2}
$